Exercises

  1. We have obtained $ S^2$ by attaching $ E^2$ to a singleton with the attaching map as the constant map on the boundary of $ E^2$. Discuss how would you obtain $ S^n$ analogously as an adjunction space.
  2. Show that if $ X$ and $ B$ are connected/path-connected then $ X\sqcup_f B $ is connected/path-connected.
  3. Describe the push out resulting from the diagram
    $ \begin{CD}
S^{n-1} @> i_1 >> E^n \\
@V{i_2}VV @.\\
E^n @. \\
\end{CD}$
  4. Show that $ S^m\times S^n$ results from attaching an $ n+m$ cell to $ S^n\vee S^m$. Hint: Let $ I$ denote $ [0, 1]$ and define a map $ f: \partial(I^n\times I^m) \longrightarrow S^n\vee S^m$ as follows

    $\displaystyle f(z) = \left\{\begin{array}{lll}
(\eta_1(x), y_0) & & \mbox{if }...
...\\
(x_0, \eta_2(y)) & & \mbox{if }\;y\in\partial I^m \\
\end{array} \right.
$

    and $ \eta_1:I^n\longrightarrow S^n$ and $ \eta_2:I^m\longrightarrow S^m$ are the quotient maps of exercise 1.
  5. Prove theorem (25.3).
  6. Fill in the details in examples (25.4) and (25.5).
in
Lecture - XXVI Seifert Van Kampen theorem and knots
in This is one of the most famous theorem concerning the fundamental group which serves as a tool for computations and applications to combinatorial group theory. If $ U$ and $ V$ are path connected open subsets of a topological space such that $ U\cap V$ is path connected, the theorem provides information on the geometry of $ U\cup V$ in terms of the geometry of $ U$, $ V$ and $ U\cap V$. In precise terms it states that the $ \pi_1$ functor maps the push-out diagram of pointed topological spaces with $ x_0\in U\cap V$,
$ \begin{CD}
(U\cap V, x_0) @> i_1 >> (U, x_0) \\
@V{i_2}VV @VV{j_1}V\\
(V, x_0) @> j_2 >> (U\cup V, x_0) \\
\end{CD}$
to the push-out diagram of groups:
$ \begin{CD}
\pi_1(U\cap V, x_0) @> {i_1}_* >> \pi_1(U, x_0) \\
@V{{i_2}_*}VV @VV{{j_1}_*}V\\
\pi_1(V, x_0) @> {j_2}_* >> \pi_1(U\cup V, x_0) \\
\end{CD}$
thereby giving a precise description of the group $ \pi_1(U\cup V, x_0)$ in terms of the groups $ \pi_1(U, x_0)$, $ \pi_1(V, x_0)$ and $ \pi_1(U\cap V, x_0)$. Thus $ \pi_1(U\cup V, x_0)$ is the free product of $ \pi_1(U, x_0)$ and $ \pi_1(V, x_0)$ amalgamated along $ \pi_1(U\cap V, x_0)$. The theorem enables us to calculate quickly the fundamental groups of several important spaces.

Subsections
nisha 2012-03-20