We work this example out in meticulous detail. Such details will be progressively
cut down and left for the students to fill in as we go along. The projective plane
is obtained by attaching a two cell to using the map given in complex form as
. Let denote the center of and
be the quotient map. Taking to be the interior of and
we apply corollary (26.7). For computing the image of we take a generator for
the infinite cyclic group
with base point . The generator is the equivalence
class of the loop
Figure:
Computing
[width=0.4]GKSBook/fig17/fig17.eps
We also need a base point sitting on the loop given by
which generates
. Taking a path joining and we get a generator
for the infinite cyclic group
namely, the class of the loop
Having set the stage we are ready to compute
namely, the homotopy class of the
loop in
.
This loop based at is homotopic to the loop
The required homotopy is
where is a map of a rectangle onto
a suitable annulus (see exercise (1)). Introducing a
we get
or in additive notation it is the map
given by
. We conclude from
corollary (26.7) that
is the cyclic group of order two.