The projective plane:

We work this example out in meticulous detail. Such details will be progressively cut down and left for the students to fill in as we go along. The projective plane $ \mathbb{R}P^2$ is obtained by attaching a two cell $ E^2$ to $ S^1$ using the map given in complex form as $ f(z) = z^2$. Let $ p$ denote the center of $ E^2$ and $ \eta:E^2\longrightarrow \mathbb{R}P^2$ be the quotient map. Taking $ U$ to be the interior of $ E^2$ and $ V = \mathbb{R}P^2 - \{p\}$ we apply corollary (26.7). For computing the image of $ i_*$ we take a generator for the infinite cyclic group $ \pi_1(U\cap V, y_0)$ with base point $ y_0 = 1/2$. The generator is the equivalence class of the loop

$\displaystyle \gamma(t) = \frac{1}{2}\exp(2\pi it),\quad 0\leq t \leq 1. \eqno(26.5)
$

Figure: Computing $ \pi_1(\mathbb RP^2)$
[width=0.4]GKSBook/fig17/fig17.eps
We also need a base point $ x_0$ sitting on the loop $ \Gamma$ given by

$\displaystyle \Gamma(t) = \eta(\exp(i\pi t)),\quad 0\leq t \leq 1, \eqno(26.6)
$

which generates $ \pi_1(\mathbb{R}P^2 - \{p\}, x_0)$. Taking a path $ \beta$ joining $ y_0$ and $ x_0$ we get a generator for the infinite cyclic group $ \pi_1(\mathbb{R}P^2 - \{p\}, y_0)$ namely, the class of the loop $ \beta *\Gamma * \beta^{-1}.$ Having set the stage we are ready to compute $ i_*[\gamma]$ namely, the homotopy class of the loop $ \gamma$ in $ \mathbb{R}P^2 - \{p\}$. This loop $ \gamma$ based at $ y_0$ is homotopic to the loop

$\displaystyle \beta * \Gamma * \Gamma * \beta^{-1}. \eqno(26.7)
$

The required homotopy is $ \eta\circ F$ where $ F$ is a map of a rectangle onto a suitable annulus (see exercise (1)). Introducing a $ \beta^{-1}*\beta$ we get

$\displaystyle i_*[\gamma] = [\beta *\Gamma *\beta^{-1}][\beta *\Gamma *\beta^{-1}] \eqno(26.8)
$

or in additive notation it is the map $ \mathbb{Z} \longrightarrow \mathbb{Z}$ given by $ n\mapsto 2n$. We conclude from corollary (26.7) that $ \pi_1(\mathbb{R}P^2)$ is the cyclic group of order two.
nisha 2012-03-20