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Module 1 : A Crash Course in Vectors

Lecture 6 : Laplacian

	$\includegraphics{fig1.36.eps}$

	One can easily extend the definition to three dimensions
	$\begin{displaymath}\delta(\vec r) = \delta(x)\delta(y)\delta(z)\end{displaymath}$
	which has the property
	$\begin{displaymath}\int f(\vec r)\delta(\vec r-\vec a)= f(\vec a)\end{displaymath}$
	provided, of course, the range of integration includes the point $\vec r = \vec a$ .