- Show that if
and
are two reflections (each with respect to a coordinate plane) then
they are conjugate by a homeomorphism. Deduce that both
and
have degree
.
- Show that if a continuous map
misses a point of
then
is
homotopic to the constant map and so has degree zero.
- Show that if
is odd then the antipodal map of
is homotopic to the identity map. Hint: Do it first for the case
and show that the homotopy may be achieved via a continuous rotation. The general case follows along
similar lines by working with pairs of coordinates.
- Show that
has the fixed point property.
- Let
be the covering projection. Show that
is the zero map.
- Show that the map (36.5) is a homeomorphism and (36.6) defines a continuous map. More generally
given a continuous map
show that the composite
induces a map
. Imitate the computation in theorem [//] of lecture [//] to
show that
when
. What happens when
?
- Prove theorem (36.11). Note that the map
given by
has degree
.
- Determine the degree of a polynomial as a map from
to itself. Reprove the fundamental theorem of algebra.
in
Lecture - XXXVII Relative homology
in
The homology groups
we have hitherto been studying are called the absolute homology groups.
The relative homology groups
that we define here
provide us a tool for understanding the geometry of a space
in relation
with its subspace
. This is facilitated by a long exact sequence in homology for the pair
. For instance if
is a retract of
, this sequence breaks off into a bunch of short exact sequences each of which splits.
The groups
are related to the absolute homology groups
for sufficiently well behaved pairs
but we shall not get into this discussion here (see [16], p. 50).
Recall that if
is a subspace of
and
is a non-trivial
cycle in
then
it may be a boundary when viewed as a cycle in
. In other words, the inclusion map
need not induce an injective map in homology. The relative homology group measures
the deviation from injectivity of the map
.
Subsections
nisha
2012-03-20