Proof:

We show that $ \delta_n = 0$ for every $ n$ which would give us the sequences (37.7). For $ c \in Z_n(X, A)$ we have the chains $ r_{\sharp}(c) \in S_n(A)$ and $ \partial _nc\in S_{n-1}(A)$. Now,

$\displaystyle \partial _nr_{\sharp}(c) = r_{\sharp}(\partial _nc) = (r_{\sharp}...
... i_{\sharp})(\partial _nc) = (r\circ i)_{\sharp}(\partial _nc) = \partial _nc
$

Hence $ \partial _nc$ is the boundary of the chain $ r_{\sharp}(c) \in S_n(A)$ and so represents the zero element in $ H_{n-1}(A)$. From lemma (37.3) we conclude that $ \delta_n$ is the zero map. The short exact sequence (37.7) splits on the left since $ H_n(r)\circ H_n(i)$ is the identity map on $ H_n(A)$. $ \square$

nisha 2012-03-20