Example 37.1

Let us calculate the relative homology groups $ H_n(X, A)$ where $ X$ is the Möbius band and $ A$ is its boundary. Since the central circle is a deformation retract of $ X$, we see that $ H_n(X) = H_n(A) = 0$ when $ n\geq 2$ and we infer from (37.3) that $ H_n(X, A) = 0$ when $ n \geq 3$. We now recall that the map $ i_*:\pi_1(A)\longrightarrow \pi_1(X)$ induced by inclusion is the group homomorphism of $ \mathbb{Z}$ into itself given by $ x \mapsto 2x$. Since the fundamental groups are abelian the map $ H_1(i) = i_*$ and so the kernel of $ H_1(i)$ is trivial. The portion of the exact sequence (37.3) with $ n = 2$ gives $ H_2(M, A) = 0$. Finally since $ H_0(i):H_0(A)\longrightarrow H_0(M)$ is an isomorphism (why?), we conclude from (37.3) (with $ n = 0$) that the map $ H_1(X)\longrightarrow H_1(X, A)$ is surjective with kernel $ 2\mathbb{Z}$. Hence $ H_1(X, A) = \mathbb{Z}_2$.

nisha 2012-03-20