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Properties of the ROC |
- The ROC of
consists of an annular region in the z-plane, centered about the origin. This property follows from equation (7.3), where we see that convergence depends on only.
- The ROC does not certain any poles. Since at poles
does not converge.
- The ROC is a connected region in z-plane. This property is proved in complex analysis.
- If
is a right sided sequence, i.e. , for , and if the circle
is in the ROC, then all finite values of , for which
will also be in the ROC.
For a right sided sequence
If is negative then we can write
Let , with , then, exists if
is finite.
The first summation is finite as it consists of a finite number of terms. In the second summation note that each term is less than
as. Since
is finite by our assumption that circle with radius lies in ROC, the second sum is also finite. Hence values of z such that
lies in ROC, except when. At , the first summation will became infinite. So if
, i.e. the sequence is causal, the value will lie in the ROC.
- If
is left sided sequence, i.e.
and
lies in the ROC, the values of function
also lie in the ROC.
The proof is similar to the property 4. The point , will lie in the ROC if the sequence is purely
anticausal
- If
is non zero for,
, then ROC is entire z-plane except possibly , and/or.
In this case the consists of finite number of terms and therefore it converges if each term infinite which is the case when is different from 0 or. lies in ROC, if
, and lies in the ROC if.
- If
is two-sided sequence and if circle
is in ROC, then ROC will consist of annular region in z-plane, which includes.
We can express a two sided sequence as sum of a right sided sequence and a left sided sequence. Then using property 4 and 5 we get this property. Using
property 2 and 3 we see what ROC will be banded by circles passing through the poles.
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