Module 3 : Microscopic Traffic Flow Modeling
Lecture 12 : Vehicle Arrival Models: Headway
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Numerical Example

Given that observed mean headway is 3.5 seconds and standard distribution is 2.6 seconds, then compute the probability that the headway lies between 0 and 0.5. Assume that the minimum expected headway is 0.5 seconds.

Solution:

First, compute the standard deviation to be used in calculation using equation [*], given that $ \mu=3.5$, $ \sigma=2.6$, and $ \alpha=0.5$. Then:

$\displaystyle \sigma=\frac{\mu-\alpha}{2}=\frac{3.5-0.5}{2}=1.5$ (1)

Second, compute the probability that headway less than zero.
$\displaystyle p(t<0)$ $\displaystyle \approx$ $\displaystyle p\left(t\le \frac{0-3.5}{1.5}\right)$  
  $\displaystyle =$ $\displaystyle p(t\le -2.33) = 0.01$  

The value 0.01 is obtained from standard normal distribution table. Similarly, compute the probability that headway less than 0.5 as
$\displaystyle p(t\le 0.5)$ $\displaystyle \approx$ $\displaystyle p\left(t\le \frac{0.5-3.5}{1.5}\right)$  
  $\displaystyle =$ $\displaystyle p(t<-2)$  
  $\displaystyle =$ $\displaystyle 0.023$  

The value 0.23 is obtained from the standard normal distribution table. Hence, the probability that headway lies between 0 and 0.5 is obtained using equation [*] as $ p(0\le t\le 0.5)$= $ 0.023-0.010 = 0.023$.