Module 2 : Electrostatics
Lecture 7 : GAUSS'S LAW
 
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  For $r>R$,
 
\begin{displaymath}4\pi r^2 \mid E\mid = \frac{Q}{r^2}\end{displaymath}
  so that
 
\begin{displaymath}\vec E = \frac{Q}{4\pi r^2} \hat r\end{displaymath}
   
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