Module 5 : Electrochemistry
Lecture 24 : Applications of Electrode Potentials.
  24.1
Introduction
By measuring the emf of suitable galvanic cells, it is possible to calculate the changes in the thermodynamic functions G, H and S, the solubility product, the pH of a solution, activities of electrolytes, and pKa and pKb. In analytical chemistry too, emf measurements have wide ranging applications.
 
G and S are determined from emf measurements and H is evaluated from the Gibbs - Helmohltz equation. Emf measurements are normally made at constant temperature. Since emf is affected by changes in temperature, the temperature coefficient of emf viz., d/dT can be determined by measuring the emf at 2 or 3 different temperatures. It is related to S as shown below. Differentiating G = -nF w.r.t. temperature (and replacing by E for convenience ),

 

d (G) /dT = - nF (dE /dT)

since d(G) /dT = - S we have

 
S = nF [dE /dT] (24.1)
H at any given temperature can be either calculated from the Gibbs-Helmholtz equation or from the following standard relation for free energy.
 
G = H - TS (24.2)
 
Example 24.1:
The galvanic cell

Ag(s) | AgCl (s) | KCl ( 1.0 M ) I Hg2 Cl2 (s) | Hg ( l )

is an example of cell without a liquid junction since both the electrodes dip into the same electrolyte. The emf of the cell is 0.058V at 298 K and 0.0614V at 308 K.

The electrode reaction are

(i) RHS electrode: Hg2Cl2 + 2e - 2Hg ( l ) + 2Cl -

LHS electrode: 2Ag (s) + 2Cl - 2AgCl+ 2e

The cell reaction is 2Ag (s ) + Hg2Cl2 (s) 2Hg ( 1 ) + 2AgCl ( s )

The thermodynamic function are calculated as shown below.

(ii) G o = -nFEo =-2 x 96500C x 0.058 V = -11194J mol -1

 
(iii) dEo /dT Eo / T = ( 0.0614 - 0.058) / 10 = 3.40 x 10 -4 VK -1
 

(iv) So = nF dEo / dT = 2 x 965000C x 3.4 x 10 -4 VK -1 = 57.9 JK -1 mol -1

 

(v) Go = Ho - TSo

    Ho = Go + TSo

    = -11194 + 298 x 57.9 = 6060 J mol -1

These details have already been described in the earlier lecture 22 and are given here for completeness and continuity.