Application of energy equation to an ideal gas
For an ideal gas in a closed system, equation of state is
|
1.160 |
|
1.161 |
|
1.162 |
U does not change with V at constant temperature.
Further, applying Theorem 2,
|
1.163 |
Hence,
|
1.164 |
Since, ![]()
|
1.165 |
From Eqs.(1.162) and Eq. (1.165) it is clear that U is neither a function of V nor a function of P at constant temperature. Only possibility is that internal energy is a function of temperature only.
For an open system
dH = Tds + Vdp |
1.166 |
From second T - dS relation,
|
1.167 |
Now,
|
1.168 |
Let, H = H(T, p)
Hence,
|
1.169 |
Comparing Eq. (1.167) and Eq. (1.168),
|
1.170 |
Now,
|
1.171 |
For an ideal gas
|
1.172 |
Hence,
|
1.173 |
∴ H does not change with p while temperature remaining unchanged.
From,
we can infer that ![]()
∴ H does not change with V while temperature remaining unchanged.









