Module 5: GROUNDWATER TRANSPORT PROCESS

Lecture 40: Solution of Diffusion Equation Using Finite Difference Method

Solution of two dimensional diffusion equation

The one-dimensional diffusion equation can be written as

                                                                         (40.20)

Consider the following initial and boundary conditions

                                              (40.21)

                                                                                      (40.22)

                                                                                       (40.23)

                                                                                     (40.24)

                                                                                     (40.25)

In this case also, we will transform the equation (40.20) using the following dimensionless variables to have better numerical stability.

                                                                                              (40.26)

                                                                                            (40.27)

                                                                                                 (40.28)

Where L1 and L2 are the length and width of the aquifer and is the simulation time .

Now we can have

                                                                               (40.29)

Similarly, we have

                                                                                        (40.30)

And,

                                                                                         (40.31)

Putting equation (40.29), (40.30), and (40.31) in (40.20), we have

                                                              (40.32)

                                                                (40.33)

Considering, Dx = Dy = D and for square domain (L1 = L2 = L ) and also considering

                                                                                                    (40.34)

We have

                                                                                 (40.35)

Now the initial and boundary conditions will be

                                      (40.36)

                                                                                       (40.37)

                                                                                       (40.38)

                                                                                      (40.39)

                                                                                       (40.40)

 

 

 

 

 

 

n+1

 

 

 

 

 

 

n


Fig. 40.4 Discretized 2D domain