Module 2 : Electrostatics
Lecture 11 : Capacitance
 

The individual voltage drops are

so that

The effective capacitance is, therefore, given by

\begin{displaymath}\frac{1}{C}= \frac{1}{C_1}+\frac{1}{C_2}+\ldots\end{displaymath}
  Example 19
 

Exercise 2

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