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  Module 3: Geometric design of highways
Lecture 16 Horizontal alignment III
  

Case (b) $L_s>L_c$

For single lane:
$\displaystyle m_1$ $\textstyle =$ $\displaystyle R-R\cos(\alpha/2)$  
$\displaystyle m_2$ $\textstyle =$ $\displaystyle \frac{(S-L_c)}{2}\sin(\alpha/2)$  

Figure 1: Set back for single lane roads ($L_s<L_c$)
\begin{figure}\centerline{\epsfig{file=../../../figeps/g15-setback-distance-single-lane,width=8cm}}\end{figure}
The set back is the sum of $m_1$ and $m_2$ given by:
\begin{displaymath}
m=R-R\cos(\alpha/2)+\frac{(S-L_c)}{2}\sin(\alpha/2)
\end{displaymath} (1)

where $\frac{\alpha}{2}=\frac{180L_c}{2\pi R}$. For multi-lane road $\frac{\alpha}{2}=\frac{180L_c}{2\pi (R-d)}$, and $m$ is given by
\begin{displaymath}
m=R-(R-d)\cos(\alpha/2)+\frac{(S-L_c)}{2}\sin(\alpha/2)
\end{displaymath} (2)