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  Module 3: Geometric design of highways
Lecture 16 Horizontal alignment III
  

Case (a) $L_s<L_c$

For single lane roads:
$\displaystyle \alpha$ $\textstyle =$ $\displaystyle \frac{s}{R}~~{\mathrm radians}$  
  $\textstyle =$ $\displaystyle \frac{180s}{\pi R}~~{\mathrm degrees}$  
$\displaystyle \alpha/2$ $\textstyle =$ $\displaystyle \frac{180s}{2\pi R}~~{\mathrm degrees}$ (1)

Therefore,
\begin{displaymath}
m=R-R\cos\left(\frac{\alpha}{2}\right)
\end{displaymath} (2)

Figure 1: Set-back for single lane roads ($L_s<L_c$)
\begin{figure}\centerline{\epsfig{file=../../../figeps/g13-setback-single-lane,width=8cm}}\end{figure}

For multi lane roads, if $d$ is the distance between centerline of the road and the centerline of the inner lane, then

\begin{displaymath}
m=R-(R-d)\cos\left(\frac{180s}{2\pi (R-d)}\right)
\end{displaymath} (3)


\begin{displaymath}
m=R-R\cos\left(\frac{\alpha}{2}\right)
\end{displaymath} (4)

Figure 2: Set-back for multi-lane roads ($L_s<L_c$)
\begin{figure}\centerline{\epsfig{file=../../../figeps/g19-setback-distance-multilane,width=8cm}}\end{figure}