EXAMPLE  3.2.2   
- Let 
 Then check that 
 Since 
 and 
 is a solution of
(3.2.1), so the set 
 is a  linearly dependent
subset of 
 
 
- Let 
 Suppose  there exists 
 such that 
 Then check that in this case we necessarily
have 
 which shows that the set  
 is a linearly independent subset of
 
 
In other words, if 
 is a
non-empty subset of a vector space 
 then to check whether the
set 
 is linearly dependent or independent, one needs to
consider the equation
  | 
(3.2.1) | 
 
In case
 
 is THE ONLY
SOLUTION of  (3.2.1),  the set 
 becomes a
linearly independent subset  of 
 Otherwise, the set 
becomes a linearly dependent subset of  
PROPOSITION  3.2.3   
Let 
 be a vector space.
- Then the zero-vector cannot
belong to a linearly independent set.
 
- If 
 is a linearly independent subset of 
then every subset of 
 is also linearly independent.
 
- If 
 is a linearly dependent subset of 
then every set containing 
 is also linearly dependent.
 
 
Proof.
 We give the proof of the first part. The reader is
required to supply the proof of other parts. 
Let 

 be a set consisting of the
zero vector. Then for any 

 Hence, for the system

 we have
a non-zero solution 

 and

 Therefore, the set 

 is linearly
dependent.
 height6pt width 6pt depth 0pt
 
THEOREM  3.2.4   
Let 
 be a linearly independent subset
of a vector space 
 Suppose there exists a vector
 such that the set
 is
linearly dependent, then 
 is a linear combination of
 
Proof.
 Since the set 

 is linearly dependent, there exist scalars 
 NOT ALL ZERO such
that
  | 
(3.2.2) | 
 
C
LAIM: 
 
Let if
possible 

 Then equation (
3.2.2)
gives 

 with not all 

 zero. Hence, by
the definition of linear independence,  the set 

 is linearly dependent which is contradictory 
to our hypothesis.  Thus, 

 and we get 
 
Note that 

 for every 

 and hence 

 for 

 Hence the result follows.
height6pt width 6pt depth 0pt
 
We now state two important corollaries of the above theorem.
We don't give their proofs as they are easy consequence of the above
theorem.
COROLLARY  3.2.5   
Let  
be a linearly dependent subset of a vector space 
 Then there
exists a smallest
 such that
 
The next corollary follows  immediately from Theorem 3.2.4
and Corollary 3.2.5.
COROLLARY  3.2.6   
Let  
 be  a linearly independent subset
of a vector space 
 Suppose there exists a vector 
 such that
 Then the set
 is also a linearly independent
subset of 
 
EXERCISE  3.2.7   
- Consider the vector space 
 Let 
 Find
all choices for the vector 
 such that the set 
 is linear independent subset of 
 Does there exist
choices for vectors 
 and 
 such that the set 
 is linearly independent subset of 
?
 
- If
none of the elements appearing along the principal diagonal of a
lower triangular matrix is zero, show that the row vectors are
linearly independent in 
 The same is true for column
vectors.
 
- Let 
 Determine whether or not the vector  
 
 
- Show that 
is linearly dependent in 
 
 
- Show that 
 is a linearly independent set in
 In general if 
 is a linearly
independent set  then 
 is
also a linearly independent set.
 
- In 
 give
an example of 
 vectors 
 and 
 such that 
 is linearly dependent but any set of 
 vectors from 
 is linearly independent.
 
- What is the maximum number
of linearly independent vectors in 
 
 
- Show
that any set of 
 vectors in 
 is linearly
dependent if 
 
 
- Is the set of vectors 
 linearly independent subset of 
 
 
- Suppose 
 is a collection of vectors such that 
 as well as 
 are vector spaces. Prove that the set 
 
is a linearly independent subset of 
 if and only if
 is a linear independent subset
of 
.
 
- Under
what conditions on 
 are the vectors 
 and 
 in 
 linearly
independent?
 
- Let 
 and 
 be a subspace of
 Further, let 
 be the subspace spanned by 
 and 
 and
 be the subspace spanned by 
 and 
 Show that if 
 and 
 then 
 
 
A K Lal
2007-09-12