EXAMPLE 3.2.2
- Let
Then check that
Since
and
is a solution of
(3.2.1), so the set
is a linearly dependent
subset of
- Let
Suppose there exists
such that
Then check that in this case we necessarily
have
which shows that the set
is a linearly independent subset of
In other words, if
is a
non-empty subset of a vector space
then to check whether the
set
is linearly dependent or independent, one needs to
consider the equation
|
(3.2.1) |
In case
is THE ONLY
SOLUTION of (3.2.1), the set
becomes a
linearly independent subset of
Otherwise, the set
becomes a linearly dependent subset of
PROPOSITION 3.2.3
Let
be a vector space.
- Then the zero-vector cannot
belong to a linearly independent set.
- If
is a linearly independent subset of
then every subset of
is also linearly independent.
- If
is a linearly dependent subset of
then every set containing
is also linearly dependent.
Proof.
We give the proof of the first part. The reader is
required to supply the proof of other parts.
Let
be a set consisting of the
zero vector. Then for any
Hence, for the system
we have
a non-zero solution
and
Therefore, the set
is linearly
dependent.
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THEOREM 3.2.4
Let
be a linearly independent subset
of a vector space
Suppose there exists a vector
such that the set
is
linearly dependent, then
is a linear combination of
Proof.
Since the set
is linearly dependent, there exist scalars
NOT ALL ZERO such
that
|
(3.2.2) |
C
LAIM:
Let if
possible
Then equation (
3.2.2)
gives
with not all
zero. Hence, by
the definition of linear independence, the set
is linearly dependent which is contradictory
to our hypothesis. Thus,
and we get
Note that
for every
and hence
for
Hence the result follows.
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We now state two important corollaries of the above theorem.
We don't give their proofs as they are easy consequence of the above
theorem.
COROLLARY 3.2.5
Let
be a linearly dependent subset of a vector space
Then there
exists a smallest
such that
The next corollary follows immediately from Theorem 3.2.4
and Corollary 3.2.5.
COROLLARY 3.2.6
Let
be a linearly independent subset
of a vector space
Suppose there exists a vector
such that
Then the set
is also a linearly independent
subset of
EXERCISE 3.2.7
- Consider the vector space
Let
Find
all choices for the vector
such that the set
is linear independent subset of
Does there exist
choices for vectors
and
such that the set
is linearly independent subset of
?
- If
none of the elements appearing along the principal diagonal of a
lower triangular matrix is zero, show that the row vectors are
linearly independent in
The same is true for column
vectors.
- Let
Determine whether or not the vector
- Show that
is linearly dependent in
- Show that
is a linearly independent set in
In general if
is a linearly
independent set then
is
also a linearly independent set.
- In
give
an example of
vectors
and
such that
is linearly dependent but any set of
vectors from
is linearly independent.
- What is the maximum number
of linearly independent vectors in
- Show
that any set of
vectors in
is linearly
dependent if
- Is the set of vectors
linearly independent subset of
- Suppose
is a collection of vectors such that
as well as
are vector spaces. Prove that the set
is a linearly independent subset of
if and only if
is a linear independent subset
of
.
- Under
what conditions on
are the vectors
and
in
linearly
independent?
- Let
and
be a subspace of
Further, let
be the subspace spanned by
and
and
be the subspace spanned by
and
Show that if
and
then
A K Lal
2007-09-12