Module 6 : Reaction Kinetics and Dynamics
Lecture 28 : Elementary Reactions and Reaction Mechanisms
 
Mechanism 2
NO (g) + NO (g) N2O2 (28.28)
 
N2O2 (g) + O2 (g) 2NO2 (g) (28.29)
In this mechanism a rapid equilibrium is not established in eq (28.28) but a steady state approximation can be used for the concentration of N2O2.
 
d [ N2 O2 ] / dt = k 1 [NO]2 - k -1 [ N2 O2] - k2 [ N2O2] [O2] (28.30)
Setting this equal to zero we get, for the concentration of [N2O2],
 
[N2O2] = k 1[NO]2 / (k-1 + k 2 [O2]) (28.31)
This equation for the constant (steady) value of [N2O2] is satisfied if k-1 is greater than k2 and k1. Only in such a situation is a small value of [ N2O2] is present, satisfying the SSA. In such a situation, [ N2O2] = (k1 / k-1)  [NO]2 and the rate law for eq (28.29) becomes
   
(1/2) d [ N O 2 ] / dt = k2 [ N2 O2 ] [ O2 ] = (k2 k 1/ k -1) [ NO ] 2 [ O2 ] (28.32)
Notice that both mechanisms give the same rate law! The only way to distinguish between the mechanisms is by detecting NO3 and / or N2O2. At present the second mechanism is favoured.