Availability in a finite process
Let x-y be a finite process in which heat is supplied reversibly to a heat engine. Taking an elementary cycle, let dQ1 be the heat received by the engine reversibly at temperature T1. Then
|
1.203 |
For the whole process x-y,

Fig. 1.24 Unavailable energy by 2 nd law of thermodynamics
|
1.204 |
Hence, maximum work obtainable is
UE = Qx - y - Wmax |
1.205 |
UE = T0(sy - sx) |
1.206 |

