Theorem 7.6:

Suppose $ \gamma_1,\; \gamma_2,\; \gamma_3 $ are three paths in $ X$ such that $ \gamma_1(1)=\gamma_2(0);\;
\gamma_2(1)=\gamma_3(0)$ then

$\displaystyle (\gamma_1 \ast \gamma_2) \ast \gamma_3 \sim \gamma_1 \ast (\gamma_2 \ast \gamma_3)
$

Hence

$\displaystyle ([\gamma_1][\gamma_2])[\gamma_3]=[\gamma_1]([\gamma_2][\gamma_3])
$



nisha 2012-03-20