Module 9 : Infinite Series, Tests of Convergence, Absolute and Conditional Convergence, Taylor and Maclaurin Series
Lecture 26 : Absolute convergence [Section 26.1]
Thus
Since , the series is divergent. Similarly, for , there exists such that
.
Once again, ,and hence the series is divergent.
For the series ,
However, the series is divergent. Similarly, for the series ,
but the series is convergent.
, the series 
is divergent. Similarly, for 
, there exists 
such that 
.
,and hence the series is divergent. 
, 
is divergent. Similarly, for the series 
, 
