Lecture - 12: Applications of Operational Amplifiers

Example - 1

Find vout and iout for the circuit shown in fig. 2. The input voltage is sinusoidal with amplitude of 0.5 V.

Fig. 2

Solution:

We begin by writing the KCL equations at both the + and – terminals of the op-amp.

For the negative terminal,

Therefore,

15 v- = vout

For the positive terminal,

This yields two equations in three unknowns, vout, v+ and v-. The third equation is the relationship between v+ and v- for the ideal OPAMP,

v+ = v-

Solving these equations, we find

vout = 10 vin = 5 sinωt V

Since 2 kΩ resistor forms the load of the op-amp, then the current iout is given by

Example - 2

For the different amplifier shown in fig. 3, verify that

Fig. 3

Solution:

Since the differential input voltage of OPAMP is negligible, therefore,

v1= vx
and v2 = vy

The input impedance of OPAMP is very large and, therefore, the input current of OPAMP is negligible.

Thus
And
From equation (E-1)

or       

From equation (E-2)

or       

The OPAMP3 is working as differential amplifier, therefore,

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