Generally, the stresses are uniform in the fibre and matrix. Thus above equation reduces to

(7.37)

Further, for equilibrium in transverse direction, we have

(7.38)

The axial and transverse strains in fibre and matrix are

(7.39)

Using Equations (7.34) and (7.39) in (7.37), we get

(7.40)

Further, using Equation (7.34) in Equation (7.38), we get

(7.41)

We solve Equations (7.40) and (7.41) for ,  and . The transverse composite strain then is obtained as

(7.42)

Finally, putting the values of  and  in the above equation, we get an expression for  as

(7.43)

where,

(7.44)

Equation (7.43) is an alternate equation for effective transverse modulus . This is also a rule of mixtures equations. It should be noted that the factors  and  are the nondimensional factors.