Second order and higher order equations occur frequently in science and engineering (like pendulum problem etc.) and hence has its own importance. It has its own flavour also. We devote this section for an elementary introduction.
Here
is an interval
contained in
and the functions
and
are real valued
continuous functions defined on
The functions
and
are called the coefficients of
Equation (8.1.1)
and
is called the non-homogeneous term or the force function.
Equation (8.1.1) is called linear homogeneous
if
and non-homogeneous if
Recall that a second order equation is called nonlinear if it is not linear.
is a second order equation which is nonlinear.
We now state an important theorem whose proof is simple and is omitted.
It is to be noted here that Theorem 8.1.5 is not an existence theorem. That is, it does not assert the existence of a solution of Equation (8.1.2).
For example, all the solutions of the Equation (8.1.2) form a
solution space. Note that
is also a solution of
Equation (8.1.2). Therefore, the solution set of a
Equation (8.1.2) is non-empty. A moments reflection on Theorem
8.1.5 tells us that the solution space of Equation (8.1.2)
forms a real vector space.
The natural question is to inquire about its dimension. This question will be answered in a sequence of results stated below.
We first recall the definition of Linear Dependence and Independence.
The functions
To proceed further and to simplify matters, we assume that
in Equation (8.1.2) and that the
function
and
are continuous on
In other words, we consider a homogeneous linear equation
The next theorem, given without proof, deals with the existence and
uniqueness of solutions
of Equation (8.1.3) with initial conditions
for some
A word of Caution: NOTE THAT THE COEFFICIENT OF
An important application of Theorem 8.1.9 is that
the equation (8.1.3) has exactly
Use initial condition on
We now show that any solution of Equation (8.1.3) is a linear
combination of
) IS
, WE HAVE TO ENSURE THIS
CONDITION.
linearly
independent solutions. In other words, the set of all solutions
over
forms a real vector space of dimension
and
be real valued continuous functions on
Then
Equation (8.1.3) has exactly two linearly
independent solutions. Moreover, if
and
are two linearly
independent solutions of Equation (8.1.3), then the solution
space is a linear combination of
and
.
and
be two unique solutions of Equation
(8.1.3) with initial conditions
(8.1.5)
The unique solutions
and
exist by virtue of Theorem
8.1.9. We now claim that
and
are linearly
independent. Consider the system of linear equations
where
and
are unknowns. If we can show that the only
solution for the system (8.1.6) is
,
then the two solutions
and
will be linearly independent.
and
to show that the only solution is indeed
. Hence the result follows.
and
.
Let
be any solution of Equation
(8.1.3) and let
and
Consider the function
defined by
is a solution of
Equation (8.1.3). Also note that
and
So,
and
are two
solution of Equation (8.1.3) with the same
initial conditions. Hence by Picard's Theorem on Existence and
Uniqueness (see Theorem 8.1.9),
or
and
corresponding to the
initial conditions
Consider a
non-singular matrix
with
Let
be a fundamental
system for the differential Equation 8.1.3 and
Then the rows of the matrix
also form a fundamental system for
Equation 8.1.3. That is, if
is a fundamental
system for Equation 8.1.3 then
is also a fundamental system whenever
is a fundamental system for
Note that
is also a fundamental
system. Here the matrix is
and
are solutions of
and
are
also solutions of
Do
and
form a fundamental set of solutions?
forms a basis for the solution space of
find another basis.