| Diffraction | ||
| Where The net amplitude at P will be sum of effect due to all the elements ds and can be obtained by integrating dEs from s=-d/2 to d/2 where d is the width of the slit. In doing so, we can first sum the amplitude produced by the symmetrically placed elements ds and then integrate it from s=0 to d/2. The contribution due to a pair of symmetrically placed element ds is Using the trigonomerical identity |
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