Module 9 : Infinite Series, Tests of Convergence, Absolute and Conditional Convergence, Taylor and Maclaurin Series
Lecture 26 : Absolute convergence [Section 26.1]
(ii)
If , then proceeding as above with such that , we will have some with
Again, for .
Since is a divergent geometric series, the series is also divergent. In case for any we can choose such that .
Thus, for .
Since is a divergent geometric series, by comparison test, the series is also divergent.
, then proceeding as above with 
such that 
, we will have some 
with 
. 
is a divergent geometric series, the series 
is also divergent. In case 
for any 
we can choose 
such that 
. 
.
is a divergent geometric series, by comparison test, the series 
is also divergent. 
.
.
.
