Lecture - 11: Applications of Operational Amplifiers

Example - 2

Find a relationship between VO and V1 through V6 in the circuit of fig. 5.

Fig. 5

Solution:

Let's consider of V1 (singly) by shorting the others i.e. the circuit then looks like as shown in fig. 6.

The current flowing through the resistor R into the i/e.

The current when passes through R, output an operational value of

Let as now consider the case of V2 with other inputs shorted, circuit looks like as shown in fig. 7.

Fig. 6

Now VO is given by

same thing to V4 and V6

net output V" = V2 + V4 + V6     (3)
From (2) & (3)

V' + V" = (V2 + V4 + V6 ) - (V1 + V3 + V5)
So VO = V2 + V4 + V6 - V1 - V3 - V5.

Fig. 7

Example - 3

    1. Show that the circuit of fig. 8 has A = VO / Vi = - K (R2 / R1) with K = 1 + R4 / R2 + R4 / R3, and Ri = R1.
    2. Specify resistance not larger than 100 K to achieve A = -200 V / V and Ri = 100 K.

    Fig. 8

Solution:



 

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