Let us consider the closed path pqrsp for which we can write,

.................................(2.52)

For and noting that inside the conductor is zero, we can write

=0.......................................(2.53)

E_t is the tangential component of the field. Therefore we find that

E_t = 0 ...........................................(2.54)

In order to determine the normal component E_n, the normal component of , at the surface of the conductor, we consider a small cylindrical Gaussian surface as shown in the Fig.12. Let represent the area of the top and bottom faces and represents the height of the cylinder. Once again, as , we approach the surface of the conductor. Since = 0 inside the conductor is zero,

.............(2.55)