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Now using  in eqn (6.23) and rearranging the terms,we will get : |
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| Neglecting recombination-regeneration which implies IDS(y) = IDS i.e. current constant throughtout the channel. |
| Integrating RHS of eqn (6.26) from 0 to VDS and LHS from 0 to L, we will get |
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| Now substituting Qn(y) from eqn (6.21) in eqn (6.27), we will get : |
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