Module 2 : Signals in Frequency Domain
Problem 12 :
 

Solution 12 :

 

 (a) Consider the signal y (t) shown below :-

 Now consider the convolution of y (t) with itself . Let the resultant figure be z (t)

Now consider y (k) and y (t-k) :

Now compare z (t) with the given signal x (t) .

Here x (t) is :

]

By comparing, we get

A= 1/2

So x(t) can be thought of a signal , which is the convolution of signal v(t) with itself where v(t) is :