(a) Consider the signal y (t) shown below :-
![](Solution_Template2_clip_image001.jpg)
Now consider the convolution of y (t) with itself
. Let the resultant figure be z (t)
![](Solution_Template2_clip_image001a.gif)
Now consider y (k) and y (t-k) :
![](Solution_Template2_clip_image002.jpg)
![](Solution_Template2_clip_image002a.jpg)
Now compare z (t) with the given signal x (t) .
Here x (t) is :
]
By comparing, we get
A= 1/2
So x(t) can be thought of a signal , which is the
convolution of signal v(t) with itself where v(t) is :
![](Solution_Template2_clip_image006.jpg)
![](Solution_Template2_clip_image007.gif)
![](Solution_Template2_clip_image007.jpg)
![](Solution_Template2_clip_image008a.gif)
![](Solution_Template2_clip_image008.jpg)
![](Solution_Template2_clip_image009.gif)