Solution 11 :
(a)
Causal system implies that the impulse
response is zero for

When
we take the derivative, strictly speaking we are not doing
a point-wise operation, but are involving h(t-Δt)
also.
However, the derivative is still
zero for any given time t0<0. so, the system
remains causal.
Stable
system requires the impulse response to be absolutely
integrable, i.e.
We
cannot generalise anything about this without sufficient
information about h(t). For example, if h
(t) = e-tu(t) then the
impulse response of the new function shows that it is
stable. But if h (t) = sin (t2)
then dh/dt is 2t cos(t2) which is not
absolutely integrable, and the system is thus unstable.
(b)
Since h (t) = 0 for t<0, the
given integral can be written as for
t>0, and the integral is easily seen to be zero for t<0.
Hence the system is necessarily causal.
For stability, we can consider a system with impulse
response h(t) = e-tu(t) so that the integral
gives the response of the new system as
which
is bounded above by e-t
u (t) and
hence is absolutely integrable
thus giving a stable system. On the other hand, we see
that systems with impulse responses like
h (t) = 1/t2
will not lead to a stable derived system.
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