Choosing , we obtain
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(8.35) |
or 
on dividing by , we obtain

Since the roots of (8.34) are , we may write

and set to obtain
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(8.36) |
As .
Thus the first factor on the left hand side of (8.36) tends to zero as no other factor may do so, since, by zero stability. is a simple zero of . Hence we may conclude that exp establishing the result.
Remark: It now follows that for sufficiently small whenever . Thus every consistent zero stable method is absolutely unstable for small positive .
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