This is the desired expression for the remainder in the Adams-Bashforth formula.
In a completely analogous manner, we find for the Adams-Moulton formula

 |
(7.26) |
where

and

The Adams-Moulton formula is obtained by neglecting the remainder term in (7.26). Again, we use the following two facts about 
-
is of constant sign in the interval and
-
is a continuous function of .
Thus applying second mean value theorem of integral calculus, we have

for some satisfying . By definition of , we have
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(7.27) |
|