The numerical solution satisfies
![](15_3_clip_image002.gif) |
(5.6) |
By the mean value theorem,
for ![](Images/image033.png)
Subtracting this from (5.6) and setting
, we get
![](Images/image037.png)
![](Images/image039.png) |
(5.7) |
Now, if we assume that satisfies a Lipschitz condition in and , as will happen in practice, we get the following bounds: ![](Images/image045.png) ![](Images/image047.png)
![](15_3_clip_image002_0001.gif)
and
![](Images/image051.png)
(by using Lipschitz condition and mean value theorem)
![](Images/image053.png) |