Proof:

Let $ {\tilde\gamma}$ be a loop in $ {\tilde X}$ based at $ {\tilde x}_0$ that represents an element of ker$ \;p_*$. This means the loop $ \gamma = p\circ {\tilde \gamma}$ is homotopic to the constant loop in $ X$ based at $ x_0$. But the constant loop $ \varepsilon_{x_0}$ at $ x_0$ lifts as the constant loop $ \varepsilon{\tilde x_0}$ at $ {\tilde x}_0 \in {\tilde X}$. By the covering homotopy theorem we conclude that $ {\tilde\gamma}$ and the constant loop $ \varepsilon_{{\tilde x}_0}$ are homotopic. That is to say $ [\tilde \gamma]$ is the trivial element in $ \pi_1({\tilde X}, {\tilde x}_0)$. $ \square$

nisha 2012-03-20