Example

Ex13-1 Data from a differential leveling have been found in the order of B.S., F.S..... etc. starting with the initial reading on B.M. (elevation 150.485 m) are as follows : 1.205, 1.860, 0.125, 1.915, 0.395, 2.615, 0.880, 1.760, 1.960, 0.920, 2.595, 0.915, 2.255, 0.515, 2.305, 1.170. The final reading closes on B.M.. Put the data in a complete field note form and carry out reduction of level by Rise and Fall method. All units are in meters.

Solution :

B.S. (m)
F.S. (m)
Rise (m)
Fall (m)
Elevation (m)
Remark
1.205
      
150.485
B.M.
0.125
1.860
 
0.655
149.830
 
0.395
1.915
 
1.7290
148.040
 
0.880
2.615
 
2.220
145.820
 
1.960
1.760
 
0.880
144.940
 
2.595
0.920
1.040
  
145.980
 
2.255
0.915
1.680
  
147.660
 
2.305
0.515
1.740
  
149.450
 
 
1.170
1.135
  
150.535
B.M.

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