Module 2 : Analysis of Statically Determinate Structures
Lecture 9 : Example for Trusses

 

 

(a) FBD of the joint B :

                                            
 
                                 
 

                               

   
        FBD of the joint A :
 

                                                         

                                
                                 
 

                       Force in AB = 22.5 kN (Compression).

 

                       Force in AD = 37.5 kN (Tension).

 

                       Force in AC = 30.0 kN (Compression).

   
 

(b) Take a section through EG , FG , FH and consider the equilibrium of part at the right side

                                                                
 

                               

                                  
 

                                
   
 

                       Force in EG = 36.0 kN (Compression).

                         Force in FG = 22.5 kN (Tension).
                         Force in FH = 18.0 kN (Compression).
 

 

 
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