Module 3 :
Method of Analyses
Lecture 14 : Methods of Characteristics [ Section 14.3 :
Strip foundations
]
=constant
now,
therefore,
now,
Numerical example
:
(assumed)
If q=0,C=1,
=0.001
=5.14=
=0,q=1.0,C=1.0,
=0.001 Therefore,
=1.0 =
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(assumed) 
=0.001 
=0,q=1.0,C=1.0, 
=1.0 = 
