The equations of equilibrium of rods
Consider an infinitesimal element of length bounded by two adjacent cross-sections of the rod. Let be the resultant internal stress on a cross section; then the force acting on this cross-section of the rod is and that acting on the other end is . If is the external force acting per unit length of the rod, then, the total force acting on the element of length is . Since the rod is in equilibrium under the action of these two forces, we have,
or |
(13.1) |
Similarly, the moment of the internal stresses are and respectively. And moment of the internal stresses about point O' is . Summing up the total moments is obtained as:
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(13.2) |
Dividing by and noting that : the unit vector tangential to the rod, we have
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(13.3) |
If is a concentrated force applied only at its free end, then = constant. Furthermore, putting and by integrating, we have constant
Similarly, we can differentiate equation 13.3 with respect to to obtain
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(13.4) |
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