Using Thevenin's equivalent

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The circuit is shown in figure 5.25, and the aim is to find . The analysis is shown in fig 5.26, 5.27, 5.28.

**Figure 5.25:**
$\includegraphics[width=3.0in]{lec4figs/25.eps}$

**Figure 5.26:**
$\includegraphics[width=3.0in]{lec4figs/26.eps}$

**Figure 5.27:**
$\includegraphics[width=3.0in]{lec4figs/27.eps}$

**Figure 5.28:**
$\includegraphics[width=3.0in]{lec4figs/28.eps}$

ynsingh 2007-07-25