Module 1 : Real Numbers, Functions and Sequences
Lecture 7 : Differentiation
8.1.1 Theorem (Chain Rule):
 

Let and be functions such that  is defined. If is differentiable at  and is differentiable at , then is differentiable at and

Alternatively, if

then,

  Proof:
 

let

Since is differentiable at , the function is defined in a neighbourhood of 0.

Further, as . Now

Letting  in the above, we get

Thus, for

Since is continuous at ,

Thus, from the above equation we get

 
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