Module 3 : MAGNETIC FIELD
Lecture 15 : Biot- Savarts' Law

The integral above may easily be evaluated by a substitution $x= r^2+z^2$. The result is

\begin{displaymath}B = \mu_0\sigma\omega\left[\frac{R^2+2z^2}{(R^2+z^2)^{3/2}}-2z\right]\end{displaymath}

The field at the centre of the disk ( $z=0$) is

\begin{displaymath}B(z=0) = \mu_0\sigma\omega R\end{displaymath}

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