Module 3 : MAGNETIC FIELD
Lecture 15 : Biot- Savarts' Law
  Example 11 : Force between two long and parallel wires.

Force due to the first wire at the position of the second wire is given by

\begin{displaymath}\vec B = -\frac{\mu_0I_1}{2\pi d}\hat k\end{displaymath}  where $\hat k$is a unit vecor out of the page. The force experienced by the second wire in this field is

\begin{eqnarray*} \vec F &=& \int (\vec{I_2}\times\vec B)dl\\ &=& -\frac{\mu_0... ...t k)\int dl\\ &=& -\frac{\mu_0I_1I_2}{2\pi d}\hat\imath\int dl \end{eqnarray*}

\includegraphics{fig3.26b.eps}

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