Module 2 : Electrostatics
Lecture 8 : Electrostatic Potential
 

Example 12 :

Potential due to a uniform electric field $\vec E$.

If the electric field is $\vec E$and is directed along the x-direction,

\begin{displaymath}\phi(x) = -\int_{x_0}^{x} E dx = - E(x-x_0)\end{displaymath}

choosing the reference point $x_0$to be at the origin,

\begin{displaymath}\phi(x) = - Ex\end{displaymath}

\includegraphics{fig28.eps}

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