Module 2 : Electrostatics
Lecture 7 : GAUSS'S LAW
  Example 8 :
Find the flux through the curved surface of a right circular cone of base radius $R$ in an external electric field $\vec E$. The cone has no charge and the electric field is normal to the base.
  Solution :
  In Example 4, we calculated the flux through the base to be $-\pi R^2 E$. As the cone does not contain any charge, by Gauss's law, the flux through the curved surface must be $ + \pi R^2 E$,
  which is the result we obtained in Example 4.

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