Module 2 : Electrostatics
Lecture 8 : Coulomb's Law
 

Example 2 :

  Find the electric field at a distance $d$ from the midpoint of a finite charged rod of length $L$ carrying a charge $Q$
  Solution :
 

Choose the coordinates as shown. Let the rod be taken along the y-axis with the origin at the centre. Divide the rod into small segments of length $dy$. The field produced by the element $dy$at a height $y$is

\begin{displaymath}dE = \frac{1}{4\pi\epsilon_0}\frac{Qdy}{L}\frac{1}{(x^2+y^2)}\end{displaymath}

is directed along $\vec{AP}$in the figure.

\includegraphics{fig6A.eps}
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