Solution 4
(a) We know that the overall impulse response of cascaded systems is the convolution of the impulse responses of the individual systems.
Let the overall impulse response of the cascaded system be .
Therefore using the above mentioned property, we have
![](Solution_Template2_clip_image015.gif)
Since the convolution is associative in nature therefore we can say that
![](Solution_Template2_clip_image017.gif)
So first convolving with itself:
Let .
Since h2[k] is non-zero for k = 0 and 1 only, therefore we can write that
![](Solution_Template2_clip_image023.gif)
Therefore:
![](Solution_Template2_clip_image025.gif)
![](Solution_Template2_clip_image027.gif)
![](Solution_Template2_clip_image029.gif)
![](Solution_Template2_clip_image031.gif)
![](Solution_Template2_clip_image033.gif)
![](Solution_Template2_clip_image035.gif)
Therefore, we have
![](Solution_Template2_clip_image037.gif)
Now h[n] is nonzero from 0 to 6 and is nonzero from 0 to 2.
Also, .
Therefore will be nonzero from 0 to 4.
( If a signal is non-zero in the interval (a , b )and it is convoluted with another signal which is non zero in the interval (c,d ) then the convoluted signal is non zero in the interval (a+c,b+d).)
Let
![](Solution_Template2_clip_image045.gif)
Now,
![](Solution_Template2_clip_image047.gif)
Therefore, we have
![](Solution_Template2_clip_image049.gif)
(from the Figure (b) we have h[0] = 1)
.
![](Solution_Template2_clip_image055.gif)
![](Solution_Template2_clip_image057.gif)
![](Solution_Template2_clip_image059.gif)
![](Solution_Template2_clip_image061.gif)
![](Solution_Template2_clip_image063.gif)
.
![](Solution_Template2_clip_image067.gif)
![](Solution_Template2_clip_image069.gif)
![](Solution_Template2_clip_image071.gif)
![](Solution_Template2_clip_image073.gif)
![](Solution_Template2_clip_image075.gif)
.
Therefore,
![](Solution_Template2_clip_image079.gif) ![](Top.gif)
(b) We have
![](Solution_Template2_clip_image081.gif)
To get the response, we have to convolve it with h[n] which we obtained in the part (a)
![](Solution_Template2_clip_image083.gif)
Proceeding as in part (a) above, i.e. putting different values of n and correspondingly calculating y[n],finally we get the answer
y[0] =1 , y[1] = 4 , y[2] = 5, y[3] = 1 , y[4] = -3 , y[5] = -4 , y[6] = -3 , y[7] = -1.
Therefore,
![](Solution_Template2_clip_image085.gif) ![](Top.gif)
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