Chapter 6 : Principles of Physical Similarity and Dimensional Analysis
Lecture 19 :


Example

Consider pressure drop in a tube of length , hydraulic diameter d, surface roughness Î, with fluid of density ρ and viscosity μ moving with average velocity ν

This can be expressed as

f (DP, U, d, , Î, ρ, μ) = 0

Now m=7 since the phenomenon involves 7 independent parameters.

We select ρ, U, d as repeating variables (so that all 3 dimensions are represented)

Now 4 π (7 - 3) parameters are determined as




Now basic units







 

All Π parameters ® M0 L0 T0

The above four equations yield

a1= -1; b1 = - 2; c1= 0
a2= -1; b2 = - 1; c2= -1
a3= 0; b3 = 0; c3= -1
a4= 0; b4 = 0; c4= -1

Thus writing                                                  

implies                                                       

Therefore,                                                 

   is called relative roughness

Similarly,   other sets of Π parameters can be chosen to describe the phenomena. Thus though it does not give the actual relationship, but it puts the data in a compact form