F1 + F2 cos 450 +F3 =0..............(A)
Smilarly, vertical force balance gives
F2 sin 450 -100=0
which gives,
F2 =100√2 =141.4 kN
Lastly taking moment about, point C,
-F1 × 1 + 100 × 2 =0
| Trusses |
Utilizing first equilibrium equation, i.e., resolving all external forces on the left part in the horizontal directon and making their algebraic sum equal to zero. |