Voltage and Current Characteristics of an SMIB System
For the analysis presented below we assume that the magnitudes of the voltages at the two ends are the same. The sending and receiving voltages are given by
 and  |
(2.57) |
where δ is angle between the sources and is usually called the load angle . As the total length of the line is l , we replace x by l to obtain the sending end voltage from (2.39) as
 |
(2.58) |
Solving the above equation we get
 |
(2.59) |
Substituting (2.59) in (2.52), the voltage equation at a point in the transmission line that is at a distance x from the receiving end is obtained as
 |
(2.60) |
In a similar way the current at that point is given by
 |
(2.61) |
Do an example
When the system is unloaded, the receiving end current is zero ( IR = 0). Therefore we can rewrite (2.58) as
 |
(2.62) |
Substituting the above equation in (2.52) and (2.53) we get the voltage and current for the unloaded system as
 |
(2.63) |
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