Lecture 25 :
Analysis of Power Swings in a Multi – Machine System
Example 1 (contd..)
Solution:
Solving the above, we get
. Now, connect the transmission line ‘b' across the network as shown in fig 25.6 and then the total impedance across the sources will be,
,
The swing impedance trajectory intersects the impedance line at
. Since the line impedance is j0.2, we can see from fig 25.7 we can see that the intersecting point of swing impedance trajectory with impedance line lies outside the transmission line ‘b'.
. Now, connect the transmission line ‘b' across the network as shown in fig 25.6 and then the total impedance across the sources will be, 
, 
. Since the line impedance is j0.2, we can see from fig 25.7 we can see that the intersecting point of swing impedance trajectory with impedance line lies outside the transmission line ‘b'. 
